Question

If A(3, 4),B (3,-3) and C ( 6, - 3) are the points, prove that AB and BC are proportional.

Plz, helpppppppp​

Answer 1

Wait..

I AM TRY TO SOLVE YR QUESTION

OKKK.

GIVE THANKS

Answer 2

Answer:

Refer to the diagram above.

First of all join AC.

Then, find the distance between

1) A and C = $\sqrt{58}$ (second picture)

2) B and C = 3 (third picture)

3) A and B = 7 (fourth picture)

Now, according to the pythagoras theorem,

Base² + Perpendicular² = Hypotenuse²

AC is the longest side. So if

BC² + AB² = AC² then it will be proved that AB and BC are proportional.

BC² + AB² = 3² + 7² = 9 + 49 = 58

AC² = $\sqrt{58 {}^{2} }$= 58

Hence AC² = BC² + AB²

Pythagoras theorem is proved.

So the angle opposite to hypotenuse will be perpendicular.

Thus, AB and BC are perpendicular.

Mark it as brainliest: )