Math, asked by seemab9656, 3 months ago

if a = 3a^2 - 4b - 1 b = 6a^2+ 3b - 8 c = 4a^ 2- ab + 3 find a-b+c

Answers

Answered by bharadwajsrivatsa
1

Answer:

Step-by-step explanation:

A-B+C

(3a 2 -4b-1)-(6a 2 +3b-8) +4a 2 -9b+3)

=3a 2 -4b-1-6a 2 -3b+8+4a 2 -9b+3

=(3+4-6) a 2+(-4-3-9) b+(-1+8+3)

=a 2+(-16) b+10

=a 2-16b+10

Answered by pandeyhimp2000
0

Answer:

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