Question

if a=-4/9,b=7/3 and c=11/6, show that (a-b)-c is not equal to a -(b-c) pls answer step by step ​

Answer 1

Answer:

(a - b) - c ≠ a - (b - c)

Step-by-step explanation:

$a=\frac{-4}{9} \\\\b=\frac{7}{3} \\\\c=\frac{11}{6}$

(a - b) - c ≠ a - (b - c)

Taking LHS,

$(a-b)-c\\\\(\frac{-4}{9} -\frac{7}{3} )-\frac{11}{6} \\\\(\frac{-4-21}{9} )-\frac{11}{6} \\\\\frac{-25}{9} -\frac{11}{6} \\\\\frac{-50-33}{18} \\\\\frac{-83}{18}$

Taking RHS,

$a-(b-c)\\\\\frac{-4}{9} -(\frac{7}{3} -\frac{11}{6} )\\\\\frac{-4}{9} -(\frac{14-11}{6} )\\\\\frac{-4}{9}-\frac{3}{6}\\\\\frac{-4}{9}-\frac{1}{2}\\\\\frac{-8-9}{18} \\\\\frac{-17}{18}$

∵ $\frac{-83}{18} \neq \frac{-17}{18}$

Hence,

(a - b) - c ≠ a - (b - c)

Answer 2

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