If A = 45 then find the value of 2sec^2A + 3cosec^2A?
Answers
Answered by
4
Answer:
Step-by-step explanation:
2 Sec^2 45° + 3Cosec^2 45°
2× (√2)^2 + 3× (√2)^2
2×2 +3×2
=10
Answer=10
dineshmeenarock:
Thanks
Answered by
0
HLW MATE!
According to your given question the answer/solution will be:✨
Putting the value of A in given equation
THEN,
2sec^2 45+3cosec^2 45
:2×2+3×2 (as sec^2 45=Root 2 and also cosec^2 45=root 2)
4+6=10
THANK U☺
According to your given question the answer/solution will be:✨
Putting the value of A in given equation
THEN,
2sec^2 45+3cosec^2 45
:2×2+3×2 (as sec^2 45=Root 2 and also cosec^2 45=root 2)
4+6=10
THANK U☺
Similar questions