Question

If A = 4x²+y²–6xy; B = 3y²+12x²+8xy; C = 6x²+8y²+6xy then Find (A–B)–C.

Answer 1

GIVEN:-

A = 4x² + y² - 6xy
B = 3y² + 12x² + 8xy
C = 6x² + 8y² + 6xy

So,

(A - B) = 4x² + y² - 6xy - 3y² - 12x² - 8xy

(A - B) = -8x² - 2y² - 14xy

(A - B) - C = -8x² - 2y² - 14xy - (6x² + 8y² + 6xy)

(A - B) - C = -14x² - 10y² - 20xy

Answer 2

Heya !!

Here is your answer..

Given,

$A \: = \: {4x}^{2} + {y}^{2} - 6xy$

$B = {3y}^{2} + {12x}^{2} + 8xy$

$C= {6x}^{2} + {8y}^{2} + 6xy$

Now,

$A - B = {4x}^{2} + {y}^{2} - 6xy - {3y}^{2} - {12x}^{2} - 8xy$

$\: \: \: \: \: = { - 8x}^{2} - {2y}^{2} - 14xy$

Also,

$(A - B) - C = ({ - 8x}^{2} - {2y}^{2} - 14xy) - {6x}^{2} + {8y}^{2} + 6xy$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = { - 14x}^{2} - {10y}^{2} - 20xy$

Hope it helps...