Question

If a=√5+1/√5-1 and b=√5-1/√5+1 then tje value of a³-b³/a²+ab+b²+a³+b³/a²-ab+b² is

Answer 1

Solution

is in attachment.........

Formula used

• (a+b)²+(a-b)²=2(a²+b²)
• (a+b)²-(a-b)²=4ab
• a³+b³=(a+b)(a²-ab+b²)
• a³-b³=(a-b)(a²+ab+b²)