Math, asked by Laliyha62, 1 year ago

If A (-5,7),B(-4,-5),C(-1,-6) and D(4,5) are the vertices of a quadrilateral Then,find the area of the quadrilateral ABCD...

Answer expecting from thrisha Didi...

Didi please help karo


aniket1001: hloo
aniket1001: will u please inbox

Answers

Answered by Anonymous
30
Hello Friend.......

___________________________
___________________________

The answer of u r question is....

Ans:

By joining Bto D you will get two Triangles ABD and BCD

The area of triangle ABD..

=1/2 [-5(-5-5)+(-4)(5-7)+4(7+5)]

=1/2 (50+8+48)

=106/2

=53 square units...

Also,

The area of triangle BCD

=1/2 [-4(-6-5)-1(5+5)+4+-5+6)

=1/2 [44-10+4]

=19 square units..

Area of Triangle ABD+ Area of Triangle BCD

So,

The area of the quadrilateral ABCD ...

=53+19

=72 square units...

___________________________
___________________________

Thank you...⭐️⭐️⭐️⭐️

Attachments:

TANU81: ^_^
aniket1001: hiii
aniket1001: tanu
aniket1001: will u inbox
Answered by wwevikash
24
⭐I'VE ATTACHED 3 PICTURES WHERE I SOLVED THE ANSWER.

⭐I HOPE THAT HELPS.

⭐PLEASE MARK MY ANSWER AS BRAINLIEST AND HA DON'T FORGET TO SAY THANKS BAWWA.
Attachments:

TANU81: ^_^
aniket1001: hloo
Similar questions
Math, 1 year ago