If A (-5,7),B(-4,-5),C(-1,-6) and D(4,5) are the vertices of a quadrilateral Then,find the area of the quadrilateral ABCD...
Answer expecting from thrisha Didi...
Didi please help karo
aniket1001:
hloo
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Hello Friend.......
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The answer of u r question is....
Ans:
By joining Bto D you will get two Triangles ABD and BCD
The area of triangle ABD..
=1/2 [-5(-5-5)+(-4)(5-7)+4(7+5)]
=1/2 (50+8+48)
=106/2
=53 square units...
Also,
The area of triangle BCD
=1/2 [-4(-6-5)-1(5+5)+4+-5+6)
=1/2 [44-10+4]
=19 square units..
Area of Triangle ABD+ Area of Triangle BCD
So,
The area of the quadrilateral ABCD ...
=53+19
=72 square units...
___________________________
___________________________
Thank you...⭐️⭐️⭐️⭐️
___________________________
___________________________
The answer of u r question is....
Ans:
By joining Bto D you will get two Triangles ABD and BCD
The area of triangle ABD..
=1/2 [-5(-5-5)+(-4)(5-7)+4(7+5)]
=1/2 (50+8+48)
=106/2
=53 square units...
Also,
The area of triangle BCD
=1/2 [-4(-6-5)-1(5+5)+4+-5+6)
=1/2 [44-10+4]
=19 square units..
Area of Triangle ABD+ Area of Triangle BCD
So,
The area of the quadrilateral ABCD ...
=53+19
=72 square units...
___________________________
___________________________
Thank you...⭐️⭐️⭐️⭐️
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