Question

if a =5 and d =1 of an AP then find 4 terms
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Answer 1

Answer:

The four terms are 5,6,7 and 8.

Step-by-step explanation:

First term(a1) = a = 5

Second term(a2) = a+d = 5+1 = 6

Third term(a3) = a+2d = 5+2×1 = 7

Fourth term(a4) = a+3d = 5+3×1 = 8

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Answer 2

Answer :

• first term = 5
• second term = 6
• third term = 7
• fourth term = 8

Step-by-step explanation :

Arithmetic Progression :

• It is the sequence of numbers such that the difference between any two successive numbers is constant.

• In AP,

     a - first term

     d - common difference

     n - number of terms

      l - last term

    aₙ - nth term

    Sₙ - sum of n terms

• General form of AP,

     a , a+d , a+2d , a+3d , ..........

• Sum of n terms,

         $\boxed{\bf S_n=\frac{n}{2}[2a+(n-1)d]} \\\\ \boxed{\bf S_n=\frac{n}{2}[a+l]}$

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Given,

• a = 5
• d = 1

nth term of AP is given by,

     aₙ = a + (n - 1)d

First term,

put n = 1,

a₁ = 5 + (1 - 1)(1)

   = 5 + 0

   = 5

Second term,

Put n = 2,

a₂ = 5 + (2 - 1)(1)

   = 5 + 1(1)

   = 5 + 1

   = 6

Third term,

put n = 3,

a₃ = 5 + (3 - 1)(1)

   = 5 + 2(1)

   = 5 + 2

   = 7

Fourth term,

Put n = 4,

a₄ = 5 + (4 - 1)(1)

   = 5 + 3(1)

   = 5 + 3

   = 8