If A= 60 and B= 30,then prove that Cot (A-B)= (CotA CotB +1)/(Cot B- CotA)
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Answer:
Step-by-step explanation: LHS: cot(A-B)
cot(60-30) =cot(30)=√3
RHS: (cot60cot30+1)/(cot30-cot60)
[{(1/√3)√3}+1]/{√3-(1/√3)} =(1+1)/{(3-1)/√3}
2/(2/√3)=√3
as LHS =RHS =√3
HENCE,PROVED
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