If a= 8+3root7 and b=1/a what will be the value of a^2 +b^2.
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Answered by
11
hey...
by putting the value of a and b...
by putting the value of a and b...
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elepqua:
very easy explanation, thank u
Answered by
3
a=8+√3
b=1/a
then a²+b² = ?
a²= (8+√3)²
= 64+3+16√3
=67+16√3
b²= 1/a²
=1/(67+16√3)
a²+b² =
67+16√3+1/(67+16√3)
1+(67+16√3)²/67+16√3
1+67²+16√3²/67+16√3
1+4489+256(3)/67+16√3
4490+786/67+16√3
5258/67+16√3
b=1/a
then a²+b² = ?
a²= (8+√3)²
= 64+3+16√3
=67+16√3
b²= 1/a²
=1/(67+16√3)
a²+b² =
67+16√3+1/(67+16√3)
1+(67+16√3)²/67+16√3
1+67²+16√3²/67+16√3
1+4489+256(3)/67+16√3
4490+786/67+16√3
5258/67+16√3
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