Question

find the area of right triangle whose hypotenuse is 26cm long and one of the sides containing the right angle measures 10cm

Answer 1

h2=p2+b2
(26×26)=10×10+b2
676=100+b2
b2=676-100
b2=576
b=square root (576)
b=24
area=1/2×b×n
1/2×24×10
area=120

Answer 2

The area of triangle is 120 cm².

Step-by-step explanation:

It is given that the the hypotenuse of a triangle is 26cm.

One of the sides containing the right angle measures 10cm.

Let the other side containing the right angle measures x cm.

According to the Pythagoras theorem

$Hypotenuse^2=Base^2+Perpendicular^2$

$(26)^2=(10)^2+Perpendicular^2$

$676=100+Perpendicular^2$

$676-100=Perpendicular^2$

$576=Perpendicular^2$

Taking square root on both sides.

$24=Perpendicular$

The there side containing the right angle measures 24 cm.

The area of a right angled triangle is

$Area=\frac{1}{2}\times base\times height$

$Area=\frac{1}{2}\times 10\times 24$

$Area=120$

Therefore, the area of triangle is 120 cm².

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