Question

if a+8√5b =8+√5/8-√5+8-√5/8+√5 find the a and b

Answer 1

Answer:

Step-by-step explanation:

GIVEN

if a+8√5b=8+√5/8-√5+8-√5/8+√5

RHS

= 8 + (√5 / 8) - √5 + 8 - (√5 / 8) + √5

MAKE IT EQUAL TO a + 8√5b

8 + (√5 / 8) - √5 + 8 - (√5 / 8) + √5 = a + 8√5b

LCM is 8

(64 + √5 - 8√5 + 64 - √5 + 8√5) / 8 = a + 8√5b

128 / 8 = a + 8√5b

16 = a + 8√5b

Can be written as

16 + (8√5) x0 = a + 8√5b

Therefore, a = 16 & b = 0

Answer 2

Answer:

a  = 135/59 , b = 0

Step-by-step explanation:

a + 8√5b = (8+√5/8-√5) + (8-√5/8+√5)

rationalize

8 + √5 / 8 - √5 x 8 + √5 / 8 + √5 + 8-√5/8+√5 x 8-√5 / 8-√5

64 + 5 + 16√5 + 64 + 5 - 16√5 / 64 - 5

= 138/59

a + 8√5b = 138/59

a = 138/59 , 8√5 x 0 = 0, thus b = 0

answer: - a = 138/59 , b = 0