If a!=a(a−1)(a−2)(a−3)...1, then find X+Y+Z, given that XYZ is a three digit number such that XYZ=X!+Y!+Z!.
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2
becausex+y+z is nothing ans
Answered by
2
Answer:
10
Step-by-step explanation:
kindly see the attachment for detailed explanation
and the number is 145
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