Question

if a and ß are zeroes of x^2 +5x + 6 find tbe value of a^-1 and B^-1​

Answer 1

To find:-

$\frac{1}{ \alpha } + \frac{1}{ \beta }$

Solution:-

$\frac{1}{ \alpha } + \frac{1}{ \beta } = \frac{ \alpha + \beta }{ \alpha \beta }$

now we know that value of

$\alpha + \beta = \frac{ - b}{a}$

and value of

$\alpha \beta = \frac{c}{a}$

putting these values.

$\large\frac{ \alpha + \beta }{ \alpha \beta } = \frac{ \frac{ - b}{a} }{ \frac{c}{a} }$

$\large \frac{ \alpha + \beta }{ \alpha \beta } = \frac{ - b}{c}$

$\large\frac{ \alpha + \beta }{ \alpha \beta } = \frac{ -(5) }{6}$

hence

$\LARGE \boxed{ \mathtt{answer = \frac{ - 5}{6} }}$