If ∠A and ∠B are acute angles such that cos A = cos B, then show that ∠ A = ∠ B.
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In triangle ABC ,
→Cos A = opposite side / hypo.
= AC / AB -------(1 )
→Cos B = adjacent side / hypo.
= BC / AB ------(2 )
→ Given that , cos A = cos B
Thus by 1 and 2,
⇒ AC / AB = BC / AB
Thus
⇒ AC . AB = BC . AB
⇒ AC = BC
→ thus, AC and BC are two sides of triangle ABC
→ angles opposite to equal sides are equal .
∴ ∠A = ∠B
HENCE PROVED
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