If a and b are the zeroes of polynomial P(x) =2x^2-5x+k such that ab=1. find the value of k.
Answers
Answered by
3
Heya !!!
P(X) = 2X² - 5X + K
Here,
A = 2 , B = -5 and C = K
Alpha × Beta = C/A
1 = K /2
K = 2.
HOPE IT WILL HELP YOU..... :-)
P(X) = 2X² - 5X + K
Here,
A = 2 , B = -5 and C = K
Alpha × Beta = C/A
1 = K /2
K = 2.
HOPE IT WILL HELP YOU..... :-)
sehaj48:
thanx
Answered by
2
Hey !!!
i am considering alpha as ' a '
and bita as ' b '
Given , ab = 1
•°• we know that
product of zeroes=constant term/cofficient of x²
that means ,
=> k/2 = 1
=> k = 2
___________________________
Hope it helps you !!;
@Rajukumar111
i am considering alpha as ' a '
and bita as ' b '
Given , ab = 1
•°• we know that
product of zeroes=constant term/cofficient of x²
that means ,
=> k/2 = 1
=> k = 2
___________________________
Hope it helps you !!;
@Rajukumar111
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