Question

If a and b are the zeroes of the quadratic polynomial P(s)=3s^2+6s+4,find the value of a/b+b/a+2/a+2/b+3ab

Answer 1

Step-by-step explanation:

Now put all these values

$\begin{gathered}\frac{ { \alpha }^{2} + { \beta }^{2} }{ \alpha \beta } + 2\bigg( \frac{ \alpha + \beta }{ \alpha \beta } \bigg) + 3 \alpha \beta \\ \\ \\ = > \frac{ \frac{4}{3} }{ \frac{4}{3} } + 2\bigg( \frac{2}{ \frac{4}{3} } \bigg) + 3 \times \frac{4}{3} \\ \\ \\ = > 1 + \frac{4 \times 3}{4} + 4 \\ \\ \\ = > 1 + 3 + 4 \\ \\ = > 8 \\ \\\end{gathered}$

Hope it helps you.