if A and B are the zeros of the quadratic polynomial p(x)=4x^2-5x-1 ,find the value of A^2B+AB^2
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d^2 = b^2-4ac
d^2 = 25-4×4×(-1)
d^2 = 25+16
d^2 = 41
A = {-b + (d)^1/2}÷2a
B = {-b - (d)^1/2}÷2a
is formula pe bnaiye
Answered by
0
Answer:
d ^2 = b ^2 -4 a
Step-by-step explanation:
d^ 2 = 25 - 4 x 4 x (-1)
d^2 = 25 + 16
d^ 2 = 41
a
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