Question

If A and B are two events such that P(A) ≠ 0 and P(B | A) = 1, then
(A) A ⊂ B
(B) B ⊂ A
(C) B = Ф
(D) A = Ф

Answer 1

Answer:

Option (A) is correct

Step-by-step explanation:

Concept:

1.conditional probability of B given A is

P(B/A)=P(A∩B)/P(A)

2.If A∩B=A then A is contained in B

Given:

P(B | A) = 1

P(A∩B)/P(A)=1

P(A∩B)=P(A)

A∩B=A

⇒ A ⊂ B