Question

if a+b=12 and ab=3 , find value of a²+b²​

Answer 1

Answer:

a+b=12 (squaring on both side))

a^2+b^2+2ab=144

a^2+b^2+2×3=144 (ab=3)

a^2+b^2+6=144

a^2+b^2=144-6

a^2+b^2=138

Answer 2

Step-by-step explanation:

a+b=12

ab=3

then the value of a²+b²

=a²+b² =(a+b)²

a² +2ab +b²

a²+2×3+b²

6+12²

6+144

150