If [a+b] 2 = 2a 2 + 2b 2 , show that a=b
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Answered by
38
Given-
[a+b]^2 = 2a^2 + 2b^2
Then we have to show that a=b
Now as we know that -
[a+b]^2 = a^2 + 2ab + b^2 -------------------- (i)
so, now according to question
[a+b]^2 = 2a^2 + 2b^2 ------------------------ (ii)
using equation (I) and (ii) we get
2a^2 + 2b^2 = a^2 + 2ab + b^2
or, a^2 + b^2 = 2ab
or, a^2 - 2ab + b^2 = 0
or, [a - b]^2 = 0 [using the formula [a-b]^2 = a^2 + 2ab + b^2 ]
so, a - b = 0
Hence a = b proved.
[a+b]^2 = 2a^2 + 2b^2
Then we have to show that a=b
Now as we know that -
[a+b]^2 = a^2 + 2ab + b^2 -------------------- (i)
so, now according to question
[a+b]^2 = 2a^2 + 2b^2 ------------------------ (ii)
using equation (I) and (ii) we get
2a^2 + 2b^2 = a^2 + 2ab + b^2
or, a^2 + b^2 = 2ab
or, a^2 - 2ab + b^2 = 0
or, [a - b]^2 = 0 [using the formula [a-b]^2 = a^2 + 2ab + b^2 ]
so, a - b = 0
Hence a = b proved.
Answered by
55
(a+b)^2=2a^2+2b^2
a^2+b^2+2ab=2a^2+2b^2
a^2+b^2=2ab
(a-b)^2=0
a-b=0
a=b
a^2+b^2+2ab=2a^2+2b^2
a^2+b^2=2ab
(a-b)^2=0
a-b=0
a=b
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