Question

if a=b^2x,b=c^2y and c=a^2z then find the value of xyz

Answer 1

a=b^2x

applying log on both sides

loga=2xlogb

x=loga/2logb


now ,b=c^2y

applying log on both sides,we get

logb=2ylogc

y=logb/2logc


now ,c=a^2z

applying log on both sides

logc=2zloga

z=logc/2loga


now, xyz=1/8



I hope this will help u ;)

Answer 2

i hope this will useful to u