Question

if|A×B|=√3(A.B) then find the angle between A and B​

Answer 1

we know,

|A×B| = ABsin∅

And

A.B = ABcos∅

A/Q:-

ABsin∅ = √3ABcos∅

sin∅/cos∅ = √3

tan∅ = √3

tan∅ = tan60°

So,

∅ = 60°

Cheers!

Answer 2

Explanation:

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