Question

If a – b = 4 and a + b = 6; find
(1) a² +62 (ii) ab​

Answer 1

Answer:

HERE IS YOUR ANSWER.

$a + b = 6$

$a - b = 4$

ADDING BOTH EQUATIONS.

$2a = 10$

$a = 5$

$5 + b = 6$

$b = 1$

1)

${a}^{2} + 62$

${5}^{2} + 62$

$25 + 62 = 87$

2) ab

$5 \times 1$

$= 5$

Step-by-step explanation:

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Answer 2

Answer:

a - b = 4

a + b = 6

2a = 10

a = 5

Now, b

a - b = 4

5- b = 4

-b = 4 - 5

-b = -1

b = 1

You can also find b from a + b = 6

5 + b = 6

b = 6-5

b = 1

Now,

(I)

${a}^{2} + 62 \\ {5}^{2} + 62 \\ 25 + 62 \\ 87$

(ii)

$ab \\ 5 \times 1 \\ 5$

This is your answer mate.

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