Question

if a-b = 4 and a+b = 6 then find ab and a2 + b2

Answer 1

a-b=4______(1)
a+b=6______(2)
from 1 and 2 we get
2a=10
a=5
put a=5 in 2 we get
b=1
so ab=5×1=5
and a^2+b&2=(5)^2+(1)^2=25+1=26

Answer 2

Answer:

$The\: value\:of \:a^{2}+b^{2}=26$

Step-by-step explanation:

Given

a-b = 4

=> a = 4+b ----(1)

and

a+b=6 ----(2)

Substitute (1) in equation (2), we get

=> 4+b+b=6

=> 4+2b=6

=> 2b=6-4

=> 2b=2

$\implies b = \frac{2}{2}$

$\implies b = 1$

Now ,

put b = 1 in equation (1), we get

a=4+1

=> a = 5

$Value\: of\: a^{2}+b^{2}\\=5^{2}+1^{2}\\=25+1\\=26$

Therefore,

$The\: value\:of \:a^{2}+b^{2}=26$

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