Question

If a-b=4 and a2+b2=40,where a and b are positive integers,then a3+b6 is equal to

Answer 1

Answer:

280

Step-by-step explanation:

Hi,

Given a - b = 4 , and a² + b² = 40

Substituting a = 4 + b in a² + b² = 40 , we get

(b + 4)² + b² = 40

=> 2b² + 8b + 16 - 40 = 0

=>2b² + 8b - 24 = 0

=>b² + 4b - 12 = 0

=> b² + 6b -2b - 12 = 0

=>(b + 6)(b - 2) = 0

=> b = 2 or -6

Given b is a positive integer

=> b = 2, a = 6

Thus, a³ + b⁶ = (6)³ + (2)⁶

= 216 + 64

= 280

Hope, it helped !

Answer 2

280 280

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ans -280