Question

if a-b=6 and ab=16;find a^+b^

Answer 1

a+b=6 ———-equation 1

a-b=4 ———-equation 2

adding both the equations,

a+b+a-b=6+4

2a=10

a=5//

Substitute a’s value in equation 1,

5+b=6

b=1//

Hence,

a²+b² = 5² + 1²

=25 + 1

26=

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Sajida Shaik

Answered Apr 8, 2017

Given a+b=6 & a-b=4

Add both the equations

We get 2a=10

a=5

Substitute a=5 in any equation

We get b=1

Now,a^2 + b^2 = 5^2 + 1^2 =25 + 1 =26

Therefore the answer is 26 :)

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Vishal Garg, Software Development Engineer Testing I at Ola Cabs (2017-present)

Answered Apr 8, 2017

This question can be solved in following way:

a+b=6, a-b=4 ==> 2a = 10 ==> a = 5

So, b = 6–5=1

That means a^2+b^2= 5^2+1^2=25+1=26.

So answer is: 26.

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Karan Raj, lives in Tiruchengodu, Tamil Nadu, India

Answered Apr 8, 2017

Provided that a+b= 6 and a-b= 4

Then (a+b)^2 = a2 + b2 + 2ab (equation 1)

Also, (a-b)^2 = a2 + b2 - 2ab (equation 2)

Adding equations 1 and 2, we get

(a+b)^2 + (a-b)^2 = 2[ a2 + b2 ]

36 + 16 = 2 [ a2 + b2 ]

52 = 2 [ a2 + b2 ]

Answer 2

Answer:

your answer is 52=2[a² + b²]

hope it will help you