Question

if a/b=7/3 then find a3-b3/b3​

Answer 1

Step-by-step explanation:

7x3-3x3-7x3/7x3

=21-6-21/21

=15-21/21

=21x15-21/21

=315-21/21

=294/21

=98/9=1x8/9

I think this is right answer

I hope you are helpful by me

Answer 2

$\mathsf \red{given} \\ \\ \mathsf{ \frac{a}{b} = \frac{7}{3} } \\ \\ \mathsf{let \: \: a = 7k \: ,\: \: b = 3k} \\ \\ \mathsf \red{substitute \: \: a = 7k \: and \: b = 3k \: in \: \: \: \frac{ {a}^{3} - {b}^{3} }{ {b}^{3} } } \\ \\ \mathsf{ = = > \: \: \: \: \frac{ {(7k)}^{3} - {(3k)}^{3} }{ {(3k)}^{3} } } \\ \\ \mathsf{ = \: \: \frac{343 {k}^{3} \: - \: 27 {k}^{3} }{ 27{k}^{3} } } \\ \\ \mathsf{ = \: \: \frac{316 {k}^{3} }{27 {k}^{3} } } \\ \\ \mathsf{ = \: \: \frac{316}{27} } \\ \\ \boxed{ \mathsf \red{ \therefore \: the \: ratio \: of \ \: \: \frac{ {a}^{3} - {b}^{3} }{ {b}^{3}} \: \: \: is \: \: \frac{316}{27} }}$

$\mathsf{}$

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