Question

if a+b=7 and ab=12 find the value of a3+b3​

Answer 1

(a+b)^³= a^³+b^³+3ab(a+b)

(7)^³=a^³+b^³+3*12*7

a^³+b^³= 343-252= 111

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Answer 2

Answer:

a + b = 7

(Cubing both sides)

( a + b )^3 = 7^3

a3 + b3 + 3ab ( a+b)= 343

Put ab=12 and a + b = 7

a3 + b3 + 3 × 12 × 7 = 343

a3 + b3 + 252 = 343

a3 + b3 = 343 - 252

a3 + b3 = 91

Therefore... a3 + b3 = 91

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