If a+b=8 and ab=6, find the value of a³+b³.
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Given : a + b = 8 and ab = 6
To find : value of a³ + b³
Solution :
By using the identity, (a + b)³ = a³ + b³ + 3ab(a + b)
On cubing a + b = 8 both sides,
(a + b)³ = 8³
(a)³ + (b)³ + 3(a )(b) (a + b) = 512
a³ + b³ + 3ab(a + b) = 512
a³ + b³ + 3 x 6 (8) = 512
[a + b = 8 and ab = 6 ]
a³ + b³ + 3 x 6 (8) = 512
a³ + b³ + 144 = 512
a³ + b³ = 512 - 144
a³ + b³ = 368
Hence the value of a³ + b³ is 368.
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