Question

If A+B=90 and secA=5/3, find cosecA

Answer 1

A+B=90=> GIVEN

SEC(A)=5/3

WE KNOW SEC(A)=1/COS(A)

THEN

COS(A)=3/5

=>ADJACENT/HYPOTENUSE=3/5

THEN ADJACENT SIDE = 3

HYPOTENUSE SIDE=5

OPPOSITE SIDE =√5²-3²=√4²=4

THEN SIN(A)=4/5

THEN COSEC(A)=1/SIN(A)=1/4/5=5/4

COSEC(A)=5/4