Question

if A+B=90 and secA=5/3,then. find the value of cosecB

Answer 1

Hi ,

Sec A = 5/3----( 1 )

A + B = 90

B = 90 - A

Cosec B = Cosec ( 90 - A )

= Sec A

= 5/3 [ from ( 1 ) ]

I hope this helps you.

:)

Answer 2

$\text{Given...}\\A+B = 90^o\\B = 90-A......(i)\\Sec \ A = \frac{5}{3}..........(ii)\\\\From (i)...\\Cosec\ B = Cosec(90-A)\\~~~~~~~~~~~~~=Sec \ A\\\~~~~~~~~~~~~~=\frac{5}{3}$