Question

If A+B , A are acute angles such that sin(A+B) = 24/25 and tanA = 3/4. Find value of cosB

Answer 1

$\tan(a )= \sin(a) \div \cos(a)$
sin a=adjcent side/hypotenuse
cos a=opposite side/hypotenuse
tan a=3/4
according to pythogaras therom


$x {}^{2} = \sqrt{s {}^{2} + s {}^{2} }$
$x { }^{2} = \sqrt{3 {}^{2} + 4 { }^{2} } = \sqrt{9 + 16 } = \sqrt{25 = } = 5$
cos b=opposite side/hypotenuse=4/5

Answer 2

Answer:

4/5

Step-by-step explanation:

tanA=SIN(A)/COS(A)

GUVEN

TAN(A)=3/4

THEN BY PYTHAGORAS theorem

THE THRD SIDE IS 5CM

NOW SIN(A)=OPPOSITE SIDE /HYPOTENUSE

COS(A)=ADJACENT SIDE/HYPOTENUSE

BUT IN THE ANGLE B IT GETS CHANGED SINCE ANGLES ARE DIFFRENT

NOW

SIN(B)=ADJACENT AIDE/HYPOTENUSE

COS(B)=OPPOSITE / HYPOTENUSE

cos(B)=4/5