if a+b+c=0 then a cube +bcube+c cube =3abc
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Answer: a³ + b³ + c³ = 3abc
a³ + b³ + c³ - 3abc = 0
(a+b+c) (a²+b²+c²-ab-bc-ca) = 0
0 x (a²+b²+c²-ab-bc-ca) = 0
0 = 0
LHS = RHS
hope it helps
tq...////
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