if a+b+c=0 then find a^2/bc+b^2/ac+c^2/ab
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Step-by-step explanation:
if a+b+c=0 , then
a= - (b+c),b=-(a+c)and c=-(a+b)
replacing the values in the question we obtain ,
(-a)^2/bc+(-b)^2/ca+(-c)^2/ab
now taking L.M.C
a^3+b^3+c^3/abc
using the identity,
if a+b+c=0 , then a^3 +b^3+c^3=3abc
hence ,we get
3abc/abc =3
therefore , the value is 3
daniaaboromman:
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