If a+b+c=0 then find the value of a²/bc +b²/ca + c²/ab.
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Answer:
3
Step-by-step explanation:
a+b+c = 0
a+b = - c …(1)
Cubing both sides,
a^3+b^3+3ab(a+b) = -c^3
a^3+b^3+c^3+3ab(-c) = 0
a^3+b^3+c^3 = 3abc
Dividing both sides by abc,
a²/bc +b²/ca + c²/ab = 3
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