Math, asked by Merrissa, 10 months ago

If a+b+c=0 then find the value of a²/bc +b²/ca + c²/ab.​

Answers

Answered by ybsv2004
1

Answer:

3

Step-by-step explanation:

a+b+c = 0

a+b = - c …(1)

Cubing both sides,

a^3+b^3+3ab(a+b) = -c^3

a^3+b^3+c^3+3ab(-c) = 0

a^3+b^3+c^3 = 3abc

Dividing both sides by abc,

a²/bc +b²/ca + c²/ab = 3

Hope this helps you!

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