If a + b + c = 0 , then the roots of the equation 4ax2 + 3bx + 2c = 0 are
(a) equal (b) imaginary (c) real (d) none of these
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Answered by
3
Answer:
Step-by-step explanation:
This kind of questions can be solved by considering an example as a, b and c can take any values
I am considering a =3
b=-2
c=-1
Such that the condition a+b+c=0 is validated
Substituting these values in the equation we get
12x²-6x-2=0
b²-4×a×c= 36+96
As the determinant value is greater than zero the roots of the equation are real.
Answered by
2
Answer:
the roots are REAL & DISTINCT
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