if a + b + c = 0, then the value of a²(b+c) + b²(c+a)+c²(a+b) is?
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we know ,
a + b + c =0
then,
a³ + b³ + c³ = 3abc --------(1)
now,
a²(b+c) +b²(c+a) +c²(a+b)
use,
a + b +c = 0
b + c = -a
in this way,
c + a = -b
a + b = -c
now,
a²( -a) + b² ( -b) +c²( -c)
-{ a³ + b³ +c³}
-3abc { from equation (1)
a + b + c =0
then,
a³ + b³ + c³ = 3abc --------(1)
now,
a²(b+c) +b²(c+a) +c²(a+b)
use,
a + b +c = 0
b + c = -a
in this way,
c + a = -b
a + b = -c
now,
a²( -a) + b² ( -b) +c²( -c)
-{ a³ + b³ +c³}
-3abc { from equation (1)
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