If a+b+c=11 ans ab+bc +ca =38 find the value of a2+b2+c2
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(a+b+c)2=a2+b2+c2+2(ab+bc+ca)
=(11)2=a2+b2+c2+2*38
=121=a2+b2+c2+76
=a2+b2+c2=121-76=45
=(11)2=a2+b2+c2+2*38
=121=a2+b2+c2+76
=a2+b2+c2=121-76=45
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