if a+b+c=11and ab + BC+ ca= 36 find the value of a×a+b×b+ c× c
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Hey!!!!
We have,
a + b + c = 11
=> Square both
=> (a + b + c)² = 121
=> a² + b² + c² + 2ab + 2bc + 2ca = 121
=> a² + b² + c² + 2(ab + bc + ca) = 121
=> a² + b² + c² + 2(36) = 121
=> a² + b² + c² = 121 - 72
=> a² + b² + c² = 49
Hope this helps
We have,
a + b + c = 11
=> Square both
=> (a + b + c)² = 121
=> a² + b² + c² + 2ab + 2bc + 2ca = 121
=> a² + b² + c² + 2(ab + bc + ca) = 121
=> a² + b² + c² + 2(36) = 121
=> a² + b² + c² = 121 - 72
=> a² + b² + c² = 49
Hope this helps
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