Question

If a + b + c = 12 and a² + b2 + c2 = 64, find the value of ab + bc + ac.
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Answer 1

Answer:

open the identity of( a + b + c )^2

= a ^2 + b ^2 + c^2 + 2 ab + 2bc + 2ca

Answer 2

$\huge\underline\mathfrak\red{Answer}$

40

Explaination...

( a +b +c )² = a² + b² + c² + 2( ab + bc + ac)

12² = 64 + 2(ab +bc +ac)

144 = 64 + 2(ab +bc +ac)

144 - 64 / 2 = (ab + bc +ac)

80/2 = (ab + bc +ac)

40 = (ab + bc +ac)

Hope it helps..✌