Question

if a+b+c=6 then evaluate (2-a)^3+(2-b)^3+(2-c)^3-3(2-a)(2-b)(2-c)​

Answer 1

Answer:

ANSWER IS 0 AS A+B+C=0..........

Answer 2

Answer:

ans is 0 because it is in the identity of a^3+b^3+c^3-3abc=(a+b+c)(a^2+b^2+c^2)+ab-bc-ca