if a+b+c=9 and ab+bc+ca 26 find a²+b²+c² it's urgent...
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Whole square a+ b + c = 9
You will get a²+b²+c² + 2ab + 2bc + 2ca= 81 (from the identity a2 + b2 + c2 + 2ab + 2bc + 2ca)
Take 2 common
a²+b²+c² +2(ab + bc + ca) = 81
a²+b²+c² + 2(26) = 81
a²+b²+c² = 81 - 52
a²+b²+c² = 27
Hope it helped :D
You will get a²+b²+c² + 2ab + 2bc + 2ca= 81 (from the identity a2 + b2 + c2 + 2ab + 2bc + 2ca)
Take 2 common
a²+b²+c² +2(ab + bc + ca) = 81
a²+b²+c² + 2(26) = 81
a²+b²+c² = 81 - 52
a²+b²+c² = 27
Hope it helped :D
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