Question

if a+b+c are all non zero and a+b+c=0, prove that a^2/bc+b^2/ca+c^2/ab=3​

Answer 1

Answer:

sorry i dont know the answer

Answer 2

Given :-----

• a+b+c are all non zero and a+b+c=0

To prove :----

• a^2/bc+b^2/ca+c^2/ab = 3 ...

Formula used :-----

• if a + b + c = 0 , than, a³+b³+c³ = 3abc..

Solution :------

Solving LHS First ,, by taking LCM we get,

→ a^2/bc+b^2/ca+c^2/ab

→ (a*a²+b*b²+c*c²)/abc

→ (a³+b³+c³)/abc

Now, it is given that, (a+b+c) = 0, so, above told formula we get, (a³+b³+c³) = 3abc.

[ putting this we get,]

→ 3abc/abc

→ 3 = RHS ..

Hence,,Proved...

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