Question

.In an A. P. the first term is 2, the last term is 29 and the sum of the terms is 155.Find the common difference. ​

Answer 1

Answer:

then sum of terms =n/2(first term +last term)

155=n/2*29+2

155=31n/2

n=155*2/31

n=10

therefore there are 10 terms in the A.P.

common difference

a+(n-1)*d=last term

2+(10-1)*d=29

2+9d=29

9d=29-2

d=27/9

d=3

therefore common difference=3

Answer 2

Answer:

hlooo dear ✌️

let ,

first term (a ) = 2

last term ( l ) = 29

sum of terms ( Sn ) = 155

so,

$sn = \frac{n}{2} (a + l)$

$155 = \frac{n}{2} (2 + 29)$

,

$310 = n(31)$

$\frac{310}{31} = n$

$n = 10$

hope it help you