if a b c are in AP then the value of a³+4b³+c³/b(a²+c²)
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Answered by
36
we can solve this by assuming the values of a,b,c so let a=0 ,b=1 ,c=2 (0,1,2 are in A.P.)
so on putting the values
=[(0)^3 + 4×(1)^3 + (2)^3]/ [1×{(0)^2 + (2)^2}]
= (4+8)/4
=3 ans
we can take any value of a,b,c ( bt in A.P.)
so on putting the values
=[(0)^3 + 4×(1)^3 + (2)^3]/ [1×{(0)^2 + (2)^2}]
= (4+8)/4
=3 ans
we can take any value of a,b,c ( bt in A.P.)
saloni2881:
thanks a lot
Answered by
15
Answer:
Hope it helps you friend. ✌
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