Question

if a, b, c are in GP, then show that -
1/a²,1/b²,1/c² are also in GP. ​

Answer 1

Answer:

Step-by-step explanation:

Solution:

As given : a, b, c are in G.P.

⇒b2=ac

The given expression :

1a2−b2+1b2

=1a2−ac+1ac

[using b2=ac]

=1a(a−c)+1ac=c+a−cac(a−c)

=aac(a−c)=1ac−c2=1b2−c2 [using ac=b2]

Answer 2

Step-by-step explanation:

1/a², 1/b², 1/c²

² x ² x ²

= 8

ᴛʜᴇɴ ɢᴘ ɪs 8

ʜᴏᴘᴇs ʜᴇʟᴘ ᴛᴏ ᴜ ..

ɪ ᴍ ʀᴀᴅʜᴀ sɪs

ᴘʟᴢ ғᴏʟʟᴏᴡ ᴍᴇ

@BᴇɪɴᴀʟʏQᴜɴᴇᴇɴ#