Question

if a,b,c,are the zeros of the polynomial P(x)=ax3+bx2+cx+d then 1/a+1/b+1/c=
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Answer 1

Solution :

The given polynomial is

P(x) = ax³ + bx² + cx + d

Since, a, b, c are the zeroes of P(x), by the relation between zeroes and coefficients, we get

• a + b + c = - b/a

• ab + bc + ca = c/a

• abc = - d/a

Now, 1/a + 1/b + 1/c

= (bc + ca + ab)/(abc)

= (c/a)/(- d/a)

= - c/d

⇒ 1/a + 1/b + 1/c = - c/d

Answer 2

here is your answer

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