Question

If a b c are zeros of a cubic poynomial then sum of squares of zeros

Answer 1

Answer:

Step-by-step explanation:

(a+b+c)² = a²+b²+c²+2ab+2bc+2ca

a²+b²+c² = (a+b+c)²-2(ab+bc+ca)

a²+b²+c² =( $\frac{- constant}{coefficient of x³}$) - 2($\frac{coefficient of x}{coefficient of x³}$

a²+b²+c² = $\frac{coefficient of x - constant}{coefficient of x³}$