If A,B,C,D and E are five prime numbers, sum of these five prime numbers =266. It is given that A<B<C<D<E, the value of A^5 is
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Answered by
27
Concept:
* All prime numbers are odd
* 2 is the only even prime number.
* 2 is the smallest prime number.
Since A,B,C,D,E are prime numbers and the sum is even,
there must be one even prime among them.
But A<B<C<D<E
This implies A=2
A^5 = 2^5 =32
subham7398:
Thanks
Answered by
0
Concept:
* All prime numbers are odd
* 2 is the only even prime number.
* 2 is the smallest prime number.
Since A,B,C,D,E are prime numbers and the sum is even,
there must be one even prime among them.
But A<B<C<D<E
This implies A=2
A^5 = 2^5 =32
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